(x^2-4x+4)(3x-7)=0

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Solution for (x^2-4x+4)(3x-7)=0 equation: 


Simplifying
(x2 + -4x + 4)(3x + -7) = 0

Reorder the terms:
(4 + -4x + x2)(3x + -7) = 0

Reorder the terms:
(4 + -4x + x2)(-7 + 3x) = 0

Multiply (4 + -4x + x2) * (-7 + 3x)
(4(-7 + 3x) + -4x * (-7 + 3x) + x2(-7 + 3x)) = 0
((-7 * 4 + 3x * 4) + -4x * (-7 + 3x) + x2(-7 + 3x)) = 0
((-28 + 12x) + -4x * (-7 + 3x) + x2(-7 + 3x)) = 0
(-28 + 12x + (-7 * -4x + 3x * -4x) + x2(-7 + 3x)) = 0
(-28 + 12x + (28x + -12x2) + x2(-7 + 3x)) = 0
(-28 + 12x + 28x + -12x2 + (-7 * x2 + 3x * x2)) = 0
(-28 + 12x + 28x + -12x2 + (-7x2 + 3x3)) = 0

Combine like terms: 12x + 28x = 40x
(-28 + 40x + -12x2 + -7x2 + 3x3) = 0

Combine like terms: -12x2 + -7x2 = -19x2
(-28 + 40x + -19x2 + 3x3) = 0

Solving
-28 + 40x + -19x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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